WITH tx as (
SELECT date_trunc('day', b.block_timestamp) as date, SUM(fee) as total_algo_fee
FROM algorand.transactions a
INNER JOIN algorand.block b on a.block_id = b.block_id
GROUP BY 1)
SELECT date, total_algo_fee, SUM(total_algo_fee) OVER (ORDER BY date ASC) as fee_sum
FROM tx