WITH lombard_funds AS (

SELECT t."from" AS address,

t.amount_usd,

t.tx_hash

FROM $query('36a622c1-563f-437d-b4e7-11ae939aad93') t

SELECT

'Lombard' AS project,

COUNT(DISTINCT address) AS total_users,

SUM(amount_usd) AS total_amount_usd,

COUNT(DISTINCT tx_hash) AS total_transactions,

FROM lombard_funds;